| Difficulty | Secondary School | High school/other |
| ★ | Basic | Easy |
| ★★ | Demanding | Basic |
| ★★★ | Demanding | |
| ★★★★ | Difficult | |
| ★★★★★ | Very difficult |
What is the total acceleration at the rim of the wheel at time t = 30.00 s?
Tip: At first, determine the tangential acceleration and the centripetal acceleration. Finally, calculate the vector sum of these.
Answer: $3{,}6\ \frac{m}{s^2}$ and the angle with respect to the radius of the wheel $\theta\approx0{,}4°$