| Difficulty | Secondary School | High school/other |
| ★ | Basic | Easy |
| ★★ | Demanding | Basic |
| ★★★ | Demanding | |
| ★★★★ | Difficult | |
| ★★★★★ | Very difficult |
Specify the average rotational speed of the wheel.
Answer: $0{,}81\ r/s$
Exercise 3.12 B
| Difficulty | Secondary School | High school/other |
| ★ | Basic | Easy |
| ★★ | Demanding | Basic |
| ★★★ | Demanding | |
| ★★★★ | Difficult | |
| ★★★★★ | Very difficult |
Specify the rotation speed of the tennis ball in rpm (revolutions per minute).
Answer: 1500 rpm
Exercise 3.12 C
| Difficulty | Secondary School | High school/other |
| ★ | Basic | Easy |
| ★★ | Demanding | Basic |
| ★★★ | Demanding | |
| ★★★★ | Difficult | |
| ★★★★★ | Very difficult |
Specify the angular velocity of the wheel.
Answer: $5{,}0\ \frac{rad}{s}-\ 5{,}1\ \frac{rad}{s}$
Exercise 3.12 D
| Difficulty | Secondary School | High school/other |
| ★ | Basic | Easy |
| ★★ | Demanding | Basic |
| ★★★ | Demanding | |
| ★★★★ | Difficult | |
| ★★★★★ | Very difficult |
What is the average velocity on the outer surface in the circular orbit of the wheel? (average speed at the rim of the wheel?)
Answer: $1{,}2\ m/s$
Exercise 3.12 E
| Difficulty | Secondary School | High school/other |
| ★ | Basic | Easy |
| ★★ | Demanding | Basic |
| ★★★ | Demanding | |
| ★★★★ | Difficult | |
| ★★★★★ | Very difficult |
What is the average centripetal acceleration at the rim of the wheel?
Answer: $6{,}2\ \frac{m}{s^2}$
Exercise 3.12 F
| Difficulty | Secondary School | High school/other |
| ★ | Basic | Easy |
| ★★ | Demanding | Basic |
| ★★★ | Demanding | |
| ★★★★ | Difficult | |
| ★★★★★ | Very difficult |
Determine the angular acceleration of the wheel.
Answer: $0{,}10\ \frac{rad}{s^2}$
Exercise 3.12 G
| Difficulty | Secondary School | High school/other |
| ★ | Basic | Easy |
| ★★ | Demanding | Basic |
| ★★★ | Demanding | |
| ★★★★ | Difficult | |
| ★★★★★ | Very difficult |
What is the tangential acceleration at the wheel rim?
Answer: $0,023\ \frac{m}{s^2}$
Exercise 3.12 H
| Difficulty | Secondary School | High school/other |
| ★ | Basic | Easy |
| ★★ | Demanding | Basic |
| ★★★ | Demanding | |
| ★★★★ | Difficult | |
| ★★★★★ | Very difficult |
What is the total acceleration at the rim of the wheel at time t = 30.00 s?
Tip: At first, determine the tangential acceleration and the centripetal acceleration. Finally, calculate the vector sum of these.
Answer: $3{,}6\ \frac{m}{s^2}$ and the angle with respect to the radius of the wheel $\theta\approx0{,}4°$
