^{}

Difficulty | Secondary School | High school/other |

★ | Basic | Easy |

★★ | Demanding | Basic |

★★★ | Demanding | |

★★★★ | Difficult | |

★★★★★ | Very difficult |

Specify the average rotational speed of the wheel.

Difficulty | Secondary School | High school/other |

★ | Basic | Easy |

★★ | Demanding | Basic |

★★★ | Demanding | |

★★★★ | Difficult | |

★★★★★ | Very difficult |

Specify the average rotational speed of the wheel.

Answer: $0{,}81\ r/s$

Difficulty | Secondary School | High school/other |

★ | Basic | Easy |

★★ | Demanding | Basic |

★★★ | Demanding | |

★★★★ | Difficult | |

★★★★★ | Very difficult |

Specify the rotation speed of the tennis ball in rpm (revolutions per minute).

Answer: 1500 rpm

Difficulty | Secondary School | High school/other |

★ | Basic | Easy |

★★ | Demanding | Basic |

★★★ | Demanding | |

★★★★ | Difficult | |

★★★★★ | Very difficult |

Specify the angular velocity of the wheel.

Answer: $5{,}0\ \frac{rad}{s}-\ 5{,}1\ \frac{rad}{s}$

Difficulty | Secondary School | High school/other |

★ | Basic | Easy |

★★ | Demanding | Basic |

★★★ | Demanding | |

★★★★ | Difficult | |

★★★★★ | Very difficult |

What is the average velocity on the outer surface in the circular orbit of the wheel? (average speed at the rim of the wheel?)

Answer: $1{,}2\ m/s$

Difficulty | Secondary School | High school/other |

★ | Basic | Easy |

★★ | Demanding | Basic |

★★★ | Demanding | |

★★★★ | Difficult | |

★★★★★ | Very difficult |

What is the average centripetal acceleration at the rim of the wheel?

Answer: $6{,}2\ \frac{m}{s^2}$

Difficulty | Secondary School | High school/other |

★ | Basic | Easy |

★★ | Demanding | Basic |

★★★ | Demanding | |

★★★★ | Difficult | |

★★★★★ | Very difficult |

Determine the angular acceleration of the wheel.

Answer: $0{,}10\ \frac{rad}{s^2}$

Difficulty | Secondary School | High school/other |

★ | Basic | Easy |

★★ | Demanding | Basic |

★★★ | Demanding | |

★★★★ | Difficult | |

★★★★★ | Very difficult |

What is the tangential acceleration at the wheel rim?

Answer: $0,023\ \frac{m}{s^2}$

Difficulty | Secondary School | High school/other |

★ | Basic | Easy |

★★ | Demanding | Basic |

★★★ | Demanding | |

★★★★ | Difficult | |

★★★★★ | Very difficult |

What is the total acceleration at the rim of the wheel at time t = 30.00 s?

Tip: At first, determine the tangential acceleration and the centripetal acceleration. Finally, calculate the vector sum of these.

Answer: $3{,}6\ \frac{m}{s^2}$ and the angle with respect to the radius of the wheel $\theta\approx0{,}4°$